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CBSE Class 10 Maths Chapter 2-Polynomials Objective Questions

CBSE Class 10 Maths Chapter 2-Polynomials Objective Questions

Polynomials is the second chapter for CBSE Class 10 Maths. It discusses the Polynomials and its applications in detail in this chapter. Students can learn about the division algorithm for polynomials of integers and also whether the zeros of quadratic polynomials are related to its coefficients from this chapter. As this is one of the important topics in Maths, it comes under the unit – Algebra.

Here, for the convenience of the students, we have compiled a list of topic-wise MCQs from this chapter. From the upcoming academic session, the objective type questions are expected to appear more often.

Solving these CBSE Class 10 Maths Objective Questions will help the students to get a proper foundation in the subject. These MCQs are compiled in the article for students to download and practice so that they get acquainted with answering the objective type of questions. Meanwhile, see here the list of sub-topics we have covered in this chapter:

2.1 Basics Revisited (2 MCQs From This Topic)

2.2 Graphical Representations (2 MCQs Covered From This Topic)

2.3 Visualization of a Polynomial (2 MCQs From This Topic)

2.4 Zeros of a Polynomial (3 MCQs From This Topic)

2.5 Factorization of polynomials (3 MCQs Asked From This Topic)

2.6 Relationship between Zeros and Coefficient (2 MCQs From The Topic)

2.7 Division Algorithm (2 MCQs Covered From This Topic)

2.8 Algebraic Identities (3 MCQs From This Topic Covered)

Solution: The constant multiplied to X 2  is the coefficient of X 2

(1) 2 + X 2  + x → coefficient of X 2  = 1

(2) 2 – X 2  + X 3  → coefficient of X 2  = -1

(3) (π/2 )  X 2 +x → coefficient of X 2  = π/2

(4) √2 x−1 → coefficient of X 2  = 0

Solution: Polynomial of degree one is called a linear polynomial.

Therefore, x−323 is a linear polynomial

are depicted in the graph shown below. Which of the polynomials does the graph 3 represent?

Solution: Consider the polynomial  where n is a positive even integer.

As the value of n increases, then the curve goes closer to the

Thus, the graph 3 represents the polynomial  x 6

are depicted in the following graph and are numbered from 1 to 3.

Answer : (A)(a)-(1), (b)-(2), (c)-(3)

Solutions: When a polynomial is of the form y=−x n  the graph of the polynomial is the mirror image of the graph of the polynomial y= x n .

Also, when the value of n increases, the graph draws closer to the y axis.

Thus, graph 1 represents y=−x 2 , graph 2 represents y=−x 3  and graph 3 represents y=−x 7

Solution: One of the zeros of the polynomial lies on the positive x-axis. Thus, the abscissa or the x -coordinate, which is the corresponding zero, is positive.

The other zero lies on the negative x-axis. Thus the abscissa or x -coordinate which is the corresponding zero, is negative.

Thus, the product of zeroes is going to be positive negative=negative.

Solution: (x-3) A (X-7) B here a and b can take any natural number values.

Solutions: If α, β and γ are the zeros of the polynomial

Solution: Here a = 1, b = -p, c = 36.

Solution: Find two numbers such that their product is -30 and sum is -7.

Solution: We know that, for a quadratic equation

ax 2 + bx+ c=0 sum of roots = α+β & product of roots = αβ

Comparing 2x 2 +x−5=0 with ax 2 + bx+ c=0, we have

Solution: We know that for a cubic polynomial ax 3 +bx 2 +cx+d Sum of zeroes =  – (b/a)

2. When the degree of the remainder is less than the degree of the divisor.

3. When the degree of the quotient is less than the degree of the divisor.

Answer: (A)Statement 1, 2 are correct

Solution: We stop the division process when either the remainder is zero or its degree is less than the degree of the divisor.

Hence, x 3 +2x 2 −9x+3= (x−3) x Quotient + 21

⇒x 3 +2x 2 −9x−18 =9x−3) x Quotient

Quotient = (x3+2x 2 −9x−18) / (x-3)

Factorizing the quotient, x 2 + 5x +6= x 2 + 3x + 2x +6 = x(x+3) +2(x+3) =(x+2) (x+3)

Hence, the factors of x 3 +2x 2 −9x−18 are x−3, x+2 and x+3

Solution: To make (a 2 +2ab) a perfect square, b 2  is to be added.

So that (a 2 +2ab+b 2 ) will become a perfect square using the identity

Here, we have compiled some 20 questions from the chapter 2 polynomials of the class 10 Maths in this downloadable PDF link that we have given in the article above.

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