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P + a ⋅ n 2 v 2 ) ( V − n ⋅ b ) = n ⋅ R ⋅ T ( P + a ⋅ n 2 v 2 ) ( V − n ⋅ b ) = n ⋅ R ⋅ T

( P + a ⋅ n 2 v 2 ) ( V − n ⋅ b ) = n ⋅ R ⋅ T ( P + a ⋅ n 2 v 2 ) ( V − n ⋅ b ) = n ⋅ R ⋅ T

( P + a n 2 V 2 ) ( V − n b ) = n R T ( P + a n 2 V 2 ) ( V − n b ) = n R T

( P + a n 2 V 2 ) ( V − n b ) = n R T ( P + a n 2 V 2 ) ( V − n b ) = n R T

P = n R T V − n b − n 2 a V 2 P = n R T V − n b − n 2 a V 2

P = ( 1 ) ( 0.0821 ) ( 350 ) 7 − ( 1 ) ( 0.0371 ) − 1 2 ( 4.17 ) 7 2 P = ( 1 ) ( 0.0821 ) ( 350 ) 7 − ( 1 ) ( 0.0371 ) − 1 2 ( 4.17 ) 7 2

Measure of the attraction between the particles (a): J * m 3 / m o l 2

Volume excluded by a mole of particles (b): m 3 / m o l

Pressure of the gas (P): p a s c a l

Van der Waals Equation Calculator is a free online tool that displays the physical properties of the gas. StudySolver online Van der Waals equation calculator tool performs the calculation faster and it displays the physical properties in a fraction of seconds.

The procedure to use the Van der Waals equation calculator is as follows:

Step 1: Enter the volume, temperature, number of moles, measure of attraction between particles in the input field

Step 2: Now click the button ”Calculate Pressure” to get the pressure of the ideal gas

Step 3: Finally, the pressure of the ideal gas using Van der Waals equation will be displayed in the output field

Van der Waals equation is an equation that provides the relationship between the volume, pressure and the absolute temperature of the real gas . It also uses two other parameters such as the intermolecular attraction and the finite size of the molecule. These two parameters are called the van der Waals parameters. Thus, the van der Waals equation is used to find the physical properties of the gas. The Van der Waals formula is given by

R is the gas constant which is equal to 8.3144598 J/ mol. K

”a” and ”b” are the Van Der Waals constants. The constant ”a” is called the attraction parameter and ”b” is called the repulsion parameter.

Determine the pressure of the gas using the Van der Waals equation where 1 mole of ammonia fills 7-litre bottle at a temperature of 350K. (a= 4.17 atm L 2 /mol 2 and b = 0.0371 L/ mol

Given that, a = 4.17 atm L 2 /mol 2

We know that, Van der Waals equation is

By rearranging the above formula to find the pressure, the formula becomes

Now, substitute the values in the formula, we get

Thus, the pressure of the real gas using Van der Waals equation is 4.04 atm

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